28/15. 1/4^2. 3 + 8/15 — Không quảng cáo

Tính \(\dfrac{{28}}{{15}} \dfrac{1}{{{4^2}}} 3 + \left( {\dfrac{8}{{15}} - \dfrac{{69}}{{60}} \dfrac{5}{{23}}} \right) \dfrac{{51}}{{54}}\)


Đề bài

Tính: \(\dfrac{{28}}{{15}}.\dfrac{1}{{{4^2}}}.3 + \left( {\dfrac{8}{{15}} - \dfrac{{69}}{{60}}.\dfrac{5}{{23}}} \right):\dfrac{{51}}{{54}}\)

  • A.

    \(\dfrac{1}{3}\)

  • B.

    \(\dfrac{{20}}{{13}}\)

  • C.

    \(3\)

  • D.

    \(\dfrac{{13}}{{20}}\)

Phương pháp giải

Thực hiện phép tính theo thứ tự: Lũy thừa => Phép tính trong ngoặc => Nhân, chia => Cộng, trừ.

\(\begin{array}{l}\dfrac{{28}}{{15}}.\dfrac{1}{{{4^2}}}.3 + \left( {\dfrac{8}{{15}} - \dfrac{{69}}{{60}}.\dfrac{5}{{23}}} \right):\dfrac{{51}}{{54}}\\ = \dfrac{{28.1.3}}{{{{15.4}^2}}} + \left( {\dfrac{8}{{15}} - \dfrac{{23.3}}{{4.3.5}}.\dfrac{5}{{23}}} \right).\dfrac{{54}}{{51}}\\ = \dfrac{{7.4.1.3}}{{3.5.4.4}} + \left( {\dfrac{8}{{15}} - \dfrac{1}{4}} \right).\dfrac{{54}}{{51}}\\ = \dfrac{7}{{20}} + \left( {\dfrac{{32}}{{60}} - \dfrac{{15}}{{60}}} \right).\dfrac{{54}}{{51}}\\ = \dfrac{7}{{20}} + \dfrac{{17}}{{60}}.\dfrac{{54}}{{51}}\\ = \dfrac{7}{{20}} + \dfrac{{17}}{{6.10}}.\dfrac{{6.3.3}}{{17.3}}\\ = \dfrac{7}{{20}} + \dfrac{3}{{10}}\\ = \dfrac{7}{{20}} + \dfrac{6}{{20}}\\ = \dfrac{{13}}{{20}}\end{array}\)

Đáp án : D