Giải bài 39 trang 40 sách bài tập Toán 6 – Cánh Diều Tập 2 — Không quảng cáo

Đề bài

Thực hiện các phép tính sau:

a) $\frac{5}{{12}} + \frac{{21}}{8}.\frac{1}{{14}}$

b) $\frac{8}{{15}}.\frac{3}{{64}} - \frac{{13}}{{25}}.$

c) $\left( {\frac{{19}}{{21}} - \frac{2}{3}} \right).\frac{{28}}{{10}}$

d) $\left( {1 - \frac{5}{{17}}} \right).\left( {\frac{3}{8} - \frac{{{5^2}}}{{24}}} \right)$

Lời giải chi tiết

a) $\frac{5}{{12}} + \frac{{21}}{8}.\frac{1}{{14}} = \frac{5}{{12}} + \frac{3}{{16}} = \frac{20}{{48}} + \frac{9}{{48}} = \frac{{29}}{{48}}$

b) $\frac{8}{{15}}.\frac{3}{{64}} - \frac{{13}}{{25}} = \frac{{8.3}}{{15.64}} - \frac{{13}}{{25}} = \frac{1}{{40}} - \frac{{13}}{{25}} \\= \frac{5}{{200}} - \frac{{104}}{{200}} = \frac{{ - 99}}{{200}}$

c) $\left( {\frac{{19}}{{21}} - \frac{2}{3}} \right).\frac{{28}}{{10}} = \left( {\frac{{19}}{{21}} - \frac{{14}}{{21}}} \right).\frac{{28}}{{10}} = \frac{5}{{21}}.\frac{{14}}{{5}} \\= \frac{2}{3}$

d) $\left( {1 - \frac{5}{{17}}} \right).\left( {\frac{3}{8} - \frac{{{5^2}}}{{24}}} \right) = \left( {\frac{{17}}{{17}} - \frac{5}{{17}}} \right).\left( {\frac{9}{{24}} - \frac{{25}}{{24}}} \right) \\= \frac{{12}}{{17}}.\frac{{ - 16}}{{24}} = \frac{{ - 8}}{{17}}$