Giải bài 28 trang 37 sách bài tập Toán 6 – Cánh Diều Tập 2 — Không quảng cáo

Đề bài

So sánh các biểu thức:

a) $A = \frac{1}{2} + \frac{{ - 3}}{8} + \frac{5}{9}$ và $B = \frac{{13}}{{ - 30}} + \frac{{17}}{{45}} + \frac{{ - 7}}{{18}}$

b) $C = \frac{{12}}{{25}} + \frac{{ - 8}}{{15}} + \frac{{ - 4}}{9}$ và $D = \frac{{ - 5}}{{12}} + \frac{4}{9} + \frac{{11}}{{ - 6}}$

c) $M = \frac{1}{3} + \frac{2}{{ - 5}} + \frac{7}{2}$ và $N = \frac{{19}}{{ - 7}} + \frac{{21}}{5} + \frac{{ - 2}}{7}$

d) $P = \frac{{34}}{{24}} + \frac{{ - 8}}{{15}} + \frac{1}{{10}}$ và $Q = \frac{8}{{21}} + 1 + \frac{1}{{ - 21}}$

Lời giải chi tiết

a) $A = \frac{1}{2} + \frac{{ - 3}}{8} + \frac{5}{9} = \frac{4}{8} + \frac{{ - 3}}{8} + \frac{5}{9} = \frac{1}{8} + \frac{5}{9} = \frac{{1.9 + 5.8}}{{8.9}} = \frac{{49}}{{72}}$

$B = \frac{{13}}{{ - 30}} + \frac{{17}}{{45}} + \frac{{ - 7}}{{18}} = \frac{{ - 39}}{{90}} + \frac{{34}}{{90}} + \frac{{ - 35}}{{90}} = \frac{{ - 39 + 34 + ( - 35)}}{{90}} = \frac{{ - 40}}{{90}} = \frac{{ - 4}}{9}$

Vì $\frac{{ - 4}}{9} < 0 < \frac{{49}}{{72}}$ nên B < A.

b) $C = \frac{{12}}{{25}} + \frac{{ - 8}}{{15}} + \frac{{ - 4}}{9} = \frac{{108}}{{225}} + \frac{{ - 120}}{{225}} + \frac{{ - 100}}{{225}} = \frac{{108 + ( - 120) + ( - 100)}}{{225}} = \frac{{ - 112}}{{225}}$

$D = \frac{{ - 5}}{{12}} + \frac{4}{9} + \frac{{11}}{{ - 6}} = \frac{{ - 15}}{{36}} + \frac{{16}}{{36}} + \frac{{ - 66}}{{36}} = \frac{{ - 15 + 16 + ( - 66)}}{{36}} = \frac{{ - 65}}{{36}}$

Mà C > -1 > D nên C > D.

c) $M = \frac{1}{3} + \frac{2}{{ - 5}} + \frac{7}{2} = \frac{{10}}{{30}} + \frac{{ - 12}}{{30}} + \frac{{105}}{{30}} = \frac{{10 + ( - 12) + (105)}}{{30}} = \frac{{103}}{{30}}$

$\begin{array}{l}N = \frac{{19}}{{ - 7}} + \frac{{21}}{5} + \frac{{ - 2}}{7} = \left( {\frac{{19}}{{ - 7}} + \frac{{ - 2}}{7}} \right) + \frac{{21}}{5} = \left( {\frac{{ - 19}}{7} + \frac{{ - 2}}{7}} \right) + \frac{{21}}{5}\\ = \frac{{ - 21}}{7} + \frac{{21}}{5} =  - 3 + \frac{{21}}{5} = \frac{{ - 15 + 21}}{5} = \frac{6}{5}\end{array}$

Mà $\frac{6}{5} = \frac{{36}}{{30}} < \frac{{103}}{{30}}$

Vậy N < M.

d) $P = \frac{{34}}{{24}} + \frac{{ - 8}}{{15}} + \frac{1}{{10}} = \frac{{17}}{{12}} + \frac{{ - 8}}{{15}} + \frac{1}{{10}} = \frac{{85}}{{60}} + \frac{{ - 32}}{{60}} + \frac{6}{{60}} = \frac{{59}}{{60}}$

$Q = \frac{8}{{21}} + 1 + \frac{1}{{ - 21}} = \left( {\frac{8}{{21}} + \frac{1}{{ - 21}}} \right) + 1 = \left( {\frac{8}{{21}} + \frac{{ - 1}}{{21}}} \right) + 1 = \frac{7}{{21}} + 1 = \frac{1}{3} + 1 = \frac{4}{3}$

Mà $\frac{4}{3} > 1 > \frac{{59}}{{60}}$

Vậy P < Q