Giải bài 41 trang 53 sách bài tập toán 7 - Cánh diều — Không quảng cáo

Đề bài

Tính:

a) $\left( {\frac{3}{4}{x^3}} \right):\left( { - \frac{1}{2}{x^2}} \right)$                                               b) $(5{x^n}):(4{x^2})$ ($n \in \mathbb{N},n \ge 2$)

c) $({x^3} - 3{x^2} + 6x):\left( { - \frac{1}{3}x} \right)$                           d) $\left( {x + \frac{1}{3}{x^2} + \frac{7}{2}{x^3}} \right):(5x)$

Lời giải chi tiết

a) $\left( {\frac{3}{4}{x^3}} \right):\left( { - \frac{1}{2}{x^2}} \right) = \frac{3}{4}:\left( { - \frac{1}{2}} \right).({x^3}:{x^2}) =  - \frac{3}{2}x$

b) $(5{x^n}):(4{x^2}) = (5:4).({x^n}:{x^2}) = \frac{5}{4}{x^{n - 2}}$

c) $({x^3} - 3{x^2} + 6x):\left( { - \frac{1}{3}x} \right) = {x^3}:\left( { - \frac{1}{3}x} \right) - 3{x^2}:\left( { - \frac{1}{3}x} \right) + 6x:\left( { - \frac{1}{3}x} \right)$

$= \left[ {1:\left( { - \frac{1}{3}} \right)} \right]({x^3}:x) - \left[ {3:\left( { - \frac{1}{3}} \right)} \right].({x^2}:x) + \left[ {6:\left( { - \frac{1}{3}} \right)} \right].(x:x)$$=  - 3{x^2} + 9x - 18$

d) $\left( {x + \frac{1}{3}{x^2} + \frac{7}{2}{x^3}} \right):(5x) = x:(5x) + \frac{1}{3}{x^2}:(5x) + \frac{7}{2}{x^3}:(5x)$

$= (1:5).(x:x) + \left( {\frac{1}{3}:5} \right).({x^2}:x) + \left( {\frac{7}{2}:5} \right).({x^3}:x)$

$= \frac{1}{5} + \frac{1}{{15}}x + \frac{7}{{10}}{x^2} = \frac{7}{{10}}{x^2} + \frac{1}{{15}}x + \frac{1}{5}$